160t-16t^2=336

Solution for 160t-16t^2=336 equation:

160t-16t^2=336

We move all terms to the left:

160t-16t^2-(336)=0

a = -16; b = 160; c = -336;
Δ = b2-4ac
Δ = 1602-4·(-16)·(-336)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-64}{2*-16}=\frac{-224}{-32}
=+7
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+64}{2*-16}=\frac{-96}{-32}
=+3
$